CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    If a point\[P(x,\text{ }y)\]moves along the ellipse \[\frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{16}=1\]and if C is the centre of the ellipse, then the sum of maximum and minimum values of CP is

    A)  25         

    B)                         9

    C)  4                            

    D)         5

    E)  16

    Correct Answer: B

    Solution :

    The given equation of ellipse is \[\frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{16}=1\] Comparing it with                 \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\] \[\Rightarrow \]               \[a=5,b=4\] and      centre of ellipse = (0, 0) \[\therefore \]Maximum distance of CP                 \[=\sqrt{{{(5-0)}^{2}}+{{(0-0)}^{2}}}=5\] and minimum distance of CP                 \[=\sqrt{{{(0-0)}^{2}}+{{(4-0)}^{2}}}=4\] \[\therefore \]  Sum \[=5+4=9\]


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