A) \[20x+23y+26z-69=0\]
B) \[31x+45y+49z+52=0\]
C) \[8x+5y+2z-69=0\]
D) \[4x+5y+6z-7=0\]
E) \[x+y+2z+17=0\]
Correct Answer: A
Solution :
Equation of plane containing plane \[x+y+z-6=0\]and\[2x+3y+4z+5=0\]is\[(x+y+z-6)+X(2x+3y+4z+5)=0\]. Since, it passes through (1, 1, 1). \[\therefore \] \[-3+\lambda .14=0\] \[\Rightarrow \] \[\lambda =\frac{3}{14}\] \[\therefore \]Required equation of plane is \[x+y+z-6+\frac{3}{14}(2x+3y+4z+5)=0\] \[\Rightarrow \]\[20x+23y+26z-69=0\]
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