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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    The equation of the plane containing the lines \[\frac{x-1}{2}=\frac{y+1}{-1}=\frac{z}{3}\]and\[\frac{x}{2}=\frac{y-2}{-1}=\frac{z+1}{3}\]is

    A)  \[8x-y+5z-8=0\]

    B)  \[8x+y-5z-7=0\]

    C)  \[x-8y+3z+6=0\]

    D)  \[8x+y-5z+7=0\]

    E)  \[x+y+z-6=0\]

    Correct Answer: B

    Solution :

    The equation of plane containing the line \[\frac{x-1}{2}=\frac{y+1}{-1}=\frac{z}{3}\] and         \[\frac{x}{2}=\frac{y-2}{-1}=\frac{x+1}{3}\] The required equation is                 \[\left| \begin{matrix}    x-1 & (y+1) & 3  \\    x & y-2 & 3+1  \\    2 & -1 & 3  \\ \end{matrix} \right|=0\] \[\Rightarrow \]\[(x-1)(3y-6+z-1)-(y+1)\]                       \[(3x-2z-2)+z(-x-2y+4)=0\] \[-5x-3y-z+5+2y-3x+2z+2+4z=0\] \[\Rightarrow \]               \[-8x-y+5z+7=0\] \[\Rightarrow \]               \[8x+y-5z-7=0\]


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