CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    The probability distribution of a random variable\[X\]is given as
    \[x\] -5 -4 -3 -2 -1 0 1 2 3 4 5
    \[P(X=x)\] P 2p 3p 4p 5p 7p 8p 9p 10p 11p 12p
    Then, the value of p is

    A)  \[\frac{1}{72}\]               

    B)         \[\frac{3}{73}\]

    C)  \[\frac{5}{72}\]               

    D)         \[\frac{1}{74}\]

    E)  \[\frac{1}{73}\]

    Correct Answer: A

    Solution :

    \[\because \] \[p+2p+3p+4p+5p+7p+8p+9p\] \[+10p+11p+12p=1\] \[\Rightarrow \]               \[72p=1\] \[\Rightarrow \]               \[p=\frac{1}{72}\]


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