CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    If A and B are mutually exclusive events and if\[p(B)=\frac{1}{3},p(A\cup B)=\frac{13}{21},\]then P is equal to

    A)  \[\frac{1}{7}\]                                  

    B)  \[\frac{4}{7}\]

    C)  \[\frac{2}{7}\]                  

    D)         \[\frac{5}{7}\]

    E)  \[\frac{6}{7}\]

    Correct Answer: C

    Solution :

    We have\[p(B)=\frac{1}{3},p(A\cup B)=\frac{13}{21}\] For mutually exclusive events A and B, we get \[p(A\cup B)=p(A)+p(B)\] \[\Rightarrow \]               \[p(A)=p(A\cup B)-p(B)\]                 \[=\frac{13}{21}-\frac{1}{3}\]                 \[=\frac{13-7}{21}=\frac{6}{21}=\frac{2}{7}\] \[\therefore \]  \[p(A)=\frac{2}{7}\]


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