CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    The distance between the origin and the normal to the curve\[y={{e}^{2x}}+{{x}^{2}}\]at\[x=0\]is

    A)  \[2\]                                    

    B)  \[\frac{2}{\sqrt{3}}\]

    C)  \[\frac{2}{\sqrt{5}}\]                    

    D)         \[\frac{1}{2}\]

    E)  \[\frac{1}{\sqrt{5}}\]

    Correct Answer: C

    Solution :

    Given curve is \[y={{e}^{2x}}+{{x}^{2}}\] \[\therefore \]  \[x=0\] \[\Rightarrow \]               \[y=1\] \[\Rightarrow \]               \[\frac{dy}{dx}=2{{e}^{2x}}+2x\]                 \[=2({{e}^{2x}}+x)\] \[\therefore \]  \[{{\left( \frac{dy}{dx} \right)}_{(0,1)}}=2\] \[\therefore \]Equation of normal at (0, 1) is                 \[y-1=-\frac{1}{2}(x-0)\] \[\Rightarrow \]               \[2y+x=2\] \[\therefore \]Required distance             \[=\left| \frac{-2}{\sqrt{{{2}^{2}}+{{1}^{2}}}} \right|\]                                                 \[=\left| -\frac{2}{\sqrt{5}} \right|\]                                                 \[=\frac{2}{\sqrt{5}}\]


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