CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    The velocity of a moving galaxy is\[300\text{ }km{{s}^{-1}}\] and the apparent change in wavelength of a spectral line emitted from the galaxy is observed as 0.5 nm. Then, the actual wavelength of the spectral line is

    A) \[3000\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    B)        \[5000\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C) \[6000\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    D)                        \[4500\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    E)                 \[5500\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: B

    Solution :

    \[v=300\text{ }km/s\] \[v=300\times {{10}^{3}}m/s\] \[\lambda =0.5\text{ }nm\] \[=0.5\times {{10}^{-9}}m,\] \[c=3\times {{10}^{8}}m/s\] \[\therefore \]  \[\frac{\Delta \lambda }{\lambda }=\frac{v}{c}\]                 \[\lambda =\frac{\Delta \lambda c}{v}\]                 \[=\frac{0.5\times {{10}^{-9}}\times 3\times {{10}^{8}}}{300\times {{10}^{3}}}\]                 \[=5\times {{10}^{-7}}=5000\,{\AA}\]


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