CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    If\[f(x)={{x}^{2}}-1\]and\[g(x)={{(x+1)}^{2}},\]then\[(gof)(x)\]is

    A)  \[{{(x+1)}^{4}}-1\]

    B)         \[{{x}^{4}}-1\]

    C)  \[{{x}^{4}}\]                     

    D)         \[{{(x+1)}^{4}}\]

    E)  \[{{(x-1)}^{4}}-1\]

    Correct Answer: C

    Solution :

    Given, \[f(x)={{x}^{2}}-1,g(x)={{(x+1)}^{2}}\] Now, \[(gof)(x)=g(f(x))\]                 \[=g({{x}^{2}}-1)\]                 \[={{({{x}^{2}}-1+1)}^{2}}\]                 \[={{x}^{4}}\]


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