CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    A vessel of depth x is half filled with oil of refractive index \[{{\mu }_{1}}\] and the other half is filled with water of refractive index\[{{\mu }_{2}}\]The apparent depth of the vessel when viewed from above is

    A)  \[\frac{x({{\mu }_{1}}+{{\mu }_{2}})}{2{{\mu }_{1}}{{\mu }_{2}}}\]         

    B)         \[\frac{x\,{{\mu }_{1}}\,{{\mu }_{2}}}{2({{\mu }_{1}}+{{\mu }_{2}})}\]

    C)  \[\frac{x{{\mu }_{1}}{{\mu }_{2}}}{({{\mu }_{1}}+{{\mu }_{2}})}\]           

    D)         \[\frac{2x({{\mu }_{1}}+{{\mu }_{2}})}{{{\mu }_{1}}{{\mu }_{2}}}\]

    E)  \[\frac{4({{\mu }_{1}}+{{\mu }_{2}})x}{{{\mu }_{1}}{{\mu }_{2}}}\]

    Correct Answer: A

    Solution :

    Apparent depth \[=\frac{\text{Real}\,\text{depth}}{\mu }\] For oil apparent depth\[=\frac{x}{2{{\mu }_{1}}}\] and for water apparent depth\[=\frac{x}{2{{\mu }_{2}}}\] The apparent depth of the vessel                                 \[=\frac{x}{2{{\mu }_{1}}}+\frac{x}{2{{\mu }_{2}}}\]                                 \[=\frac{x}{2}\left[ \frac{1}{{{\mu }_{1}}}+\frac{1}{{{\mu }_{2}}} \right]=\frac{x}{2}\left[ \frac{{{\mu }_{1}}+{{\mu }_{2}}}{{{\mu }_{1}}{{\mu }_{2}}} \right]\]


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