A) 3
B) \[4\]
C) 2
D) \[\sqrt{3}\]
E) \[\sqrt{2}\]
Correct Answer: A
Solution :
Equation\[2{{x}^{2}}+2\sqrt{6}x+a=0\]has equal roots, if \[{{b}^{2}}-4ac=0\] \[\Rightarrow \] \[24-4\times 2\times a=0\] \[\Rightarrow \] \[a=3\]
You need to login to perform this action.
You will be redirected in
3 sec
