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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    If the roots of the equation\[{{x}^{2}}-bx+c=0\]are two consecutive integers, then\[{{b}^{2}}-4c\]is

    A)  \[-1\]                   

    B)         0

    C)  1                            

    D)         2

    E)  3

    Correct Answer: C

    Solution :

    Let 1 and 2 be root of equation \[{{x}^{2}}-bx+c=0\] \[{{1}^{2}}-b\times 1+c=0\] \[b-c=1\]                                             ...(i) Similarly, \[\Rightarrow \]               \[22-b{{x}^{2}}+c=0\] \[\Rightarrow \]              \[2b-c=4\]                                             ...(ii) Solving Eqs. (i) and (ii), we get \[b=3,\text{ }c=2\] \[\therefore \] \[{{b}^{2}}-4c={{3}^{2}}-4\times 2=9-8=1\]


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