CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    If\[^{56}{{P}_{r+6}}{{:}^{54}}{{p}_{r+3}}=30800:1,\]then the value of r is

    A)  40                                         

    B)  51

    C)  101                       

    D)         410

    E)  41

    Correct Answer: E

    Solution :

    We have\[^{56}{{p}_{r+6}}{{:}^{54}}{{p}_{r+3}}=30800:1\] \[\Rightarrow \]               \[\frac{^{56}{{p}_{r+6}}}{^{54}{{p}_{r+3}}}=\frac{30800}{1}\]                 \[\frac{\frac{(56)!}{(56-r-6)!}}{\frac{(54)!}{(54-r-3)!}}=30800\] \[\Rightarrow \]               \[\frac{56!}{54!}\times \frac{(51-r)!}{(50-r)!}=30800\] \[\Rightarrow \]               \[56\times 55\times (51-r)=30800\] \[\Rightarrow \]               \[51-r=10\] \[\Rightarrow \]               \[r=41\]


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