A) \[r\left( \frac{q+p}{pq} \right)\]
B) \[r\left( \frac{q-p}{pq} \right)\]
C) \[r\frac{(p-q)}{pq}\]
D) \[r\left( \frac{p+q}{p-q} \right)\]
E) \[r\left( \frac{p-q}{p+q} \right)\]
Correct Answer: B
Solution :
Since, line\[px-qy=r\]intersects the coordinate axes at (a, 0) and (0, b). \[\therefore \] \[p.a-q.0=r\] \[\Rightarrow \] \[a=\frac{r}{p}\] And \[p.0-q.b=r\] \[\Rightarrow \] \[b=-\frac{r}{q}\] \[\therefore \] \[a+b=\frac{r}{p}-\frac{r}{q}=r\left( \frac{q-p}{pq} \right)\] \[\Rightarrow \] \[a+b=r\left( \frac{q-p}{pq} \right)\]
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