CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    The equation of a straight line which passes through the point\[(a{{\cos }^{3}}\theta ,a{{\sin }^{3}}\theta )\]and perpendicular to\[x\sec \theta +y\cos ec\theta =a\]is

    A)  \[\frac{x}{a}+\frac{y}{a}=a\cos \theta \]

    B)  \[x\text{ }cos\theta -y\text{ }sin\theta =a\text{ }cos2\theta \]

    C)  \[x\text{ }cos\theta +y\text{ }sin\theta =a\text{ }cos\text{ }2\theta \]

    D)  \[x\text{ }cos\theta +y\text{ }sin\theta -a\text{ }cos\text{ }2\theta =1\]

    E)  \[x\text{ }cos\theta -y\text{ }sin\theta +a\text{ }cos\text{ }2\theta =-1\]

    Correct Answer: A

    Solution :

    Equation of line perpendicular to  is This line possess through                     Required equation of line is


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