question_answer

If the two circles\[{{(x+7)}^{2}}+{{(y-3)}^{2}}=36\]and \[{{(x-5)}^{2}}+{{(y+2)}^{2}}=49\]touch each other externally, then the point of contact is

A)  \[\left( \frac{-19}{13},\frac{19}{13} \right)\]                       

B)  \[\left( \frac{-19}{13},\frac{9}{13} \right)\]

C)  \[\left( \frac{17}{13},\frac{9}{13} \right)\]           

D)         \[\left( \frac{-17}{13},\frac{9}{13} \right)\]

E)  \[\left( \frac{19}{13},\frac{19}{13} \right)\]

Correct Answer: B

Solution :

We have Centreand radius and      Centre and radius Point of contact