A) \[{{10}^{6}}/{{m}^{3}}\]
B) \[{{10}^{22}}/{{m}^{3}}\]
C) \[2\times {{10}^{6}}/{{m}^{3}}\]
D) \[{{10}^{19}}/{{m}^{3}}\]
E) \[2\times {{10}^{9}}/{{m}^{3}}\]
Correct Answer: E
Solution :
\[{{({{n}_{i}})}^{2}}={{n}_{e}}{{n}_{h}}\] \[{{({{10}^{16}})}^{2}}={{n}_{e}}\times 5\times {{10}^{22}}\] \[\therefore \] \[{{n}_{e}}=\frac{{{10}^{16}}\times {{10}^{16}}}{5\times {{10}^{22}}}\] \[{{n}_{e}}=2\times {{10}^{9}}/{{m}^{3}}\]
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