CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    The distance of the midpoint of line joining two points (4, 0) and (0, 4) from the centre of the circle\[{{x}^{2}}+{{y}^{2}}=16\]is

    A)  \[\sqrt{2}\]                                       

    B)  \[2\sqrt{2}\]

    C)  \[3\sqrt{2}\]                     

    D)         \[2\sqrt{3}\]

    E)  \[\sqrt{3}\]

    Correct Answer: B

    Solution :

    The midpoint of (4, 0) and (0, 4) is Required distance


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