CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    A stone of mass 2 kg is tied to a string of length 0.5 m. If the breaking tension of the string is 900 N, then the maximum angular velocity, the stone can have in uniform circular motion is

    A)  \[30\,rad{{s}^{-1}}\]       

    B)         \[20\,rad{{s}^{-1}}\]

    C)  \[10\,rad{{s}^{-1}}\]       

    D)         \[25\,rad{{s}^{-1}}\]

    E)  \[40\,rad{{s}^{-1}}\]

    Correct Answer: A

    Solution :

    The tension\[T=mr{{\omega }^{2}}\] \[{{\omega }^{2}}=\frac{T}{mr}=\frac{900}{2\times 0.5}\] \[{{\omega }^{2}}=900\] \[\omega =30\,rad/s\]


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