CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    Moment of inertia of a ring of mass M and radius R about a tangent to the circle of the ring is

    A)  \[\frac{5}{2}M{{R}^{2}}\]                            

    B)  \[\frac{3}{2}M{{R}^{2}}\]

    C)  \[\frac{1}{2}M{{R}^{2}}\]            

    D)         \[M{{R}^{2}}\]

    E)  \[\frac{7}{2}M{{R}^{2}}\]

    Correct Answer: B

    Solution :

    Moment of inertia of a ring about a tangent                 \[{{I}_{t}}=\frac{M{{R}^{2}}}{2}+M{{R}^{2}}\]                 \[=\frac{3}{2}M{{R}^{2}}\]


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