CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    If the escape velocity of a planet is 3 times that of the earth and its radius is 4 times that of the earth, then the mass of the planet is (Mass of the earth\[=6\times {{10}^{24}}kg\])

    A)  \[1.62\times {{10}^{22}}kg\]

    B)         \[0.72\times {{10}^{22}}kg\]

    C)  \[2.16\times {{10}^{26}}kg\]

    D)         \[1.22\times {{10}^{22}}kg\]

    E)  \[3.6\times {{10}^{22}}kg\]

    Correct Answer: C

    Solution :

    Escape velocity of a planet \[=3\times \] Escape velocity of the earth                 \[\sqrt{\frac{2G{{M}_{p}}}{{{R}_{p}}}}=3\sqrt{\frac{2G{{M}_{e}}}{{{R}_{e}}}}\]                 \[\frac{{{M}_{p}}}{{{R}_{p}}}=9\frac{{{M}_{e}}}{{{R}_{e}}}\]                 \[\frac{{{M}_{p}}}{4{{R}_{e}}}=9\frac{{{M}_{e}}}{{{R}_{e}}}\] \[\therefore \]  \[{{M}_{p}}=36{{M}_{e}}=36\times 6\times {{10}^{24}}\]                 \[=2.16\times {{10}^{26}}kg\]


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