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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    The compressibility of water is \[6\times {{10}^{-10}}{{N}^{-1}}{{m}^{2}}\]. If one litre is subjected to a pressure of \[4\times {{10}^{7}}N{{m}^{-2}},\]the decrease in its volume is

    A)  2.4 cc                                   

    B)  10 cc

    C)  24 cc                    

    D)         15 cc

    E)  12 cc

    Correct Answer: C

    Solution :

    \[B=\frac{1}{compressibility}=\frac{pV}{dV}\] \[\frac{1}{6\times {{10}^{-10}}}=\frac{4\times {{10}^{7}}\times 1}{dV}\] \[dV=24\times {{10}^{-3}}litre\] \[=24\text{ }cc\]


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