A) 600 K
B) 2400 K
C) 1200 K
D) 300 K
E) 4800 K
Correct Answer: E
Solution :
\[\sqrt{\frac{3R{{T}_{O}}}{{{M}_{O}}}}=\sqrt{\frac{3R{{T}_{H}}}{{{M}_{H}}}}\] or \[\frac{{{T}_{O}}}{{{M}_{O}}}=\frac{{{T}_{H}}}{{{M}_{H}}}\] or \[\frac{{{T}_{O}}}{32}=\frac{300}{2}\] or \[{{T}_{O}}=16\times 300\] \[=4800\,K\]
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