question_answer

Three capacitors are connected in the arms of a triangle ABC as shown in figure. 5 V is applied between A and B. The voltage between B and C is

A)  2 V                        

B)         1 V

C)  3 V                        

D)         1.5 V

E)  0.5 V

Correct Answer: A

Solution :

Charge across the combination of\[2\mu F\]and \[3\mu F=\]charge across\[3\mu F\]. \[\therefore \]  \[\frac{2\times 3}{2+3}\times 5=3\times {{V}_{1}}\] \[{{V}_{1}}=2\,V\]