CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    Two wires with currents 2A and 1A are enclosed in a circular loop. Another wire with current 3 A is situated outside the loop as shown. Then\[\oint{\overrightarrow{B}}.\overrightarrow{dl}\]around the loop is

    A)  \[{{\mu }_{0}}\]              

    B)         \[3{{\mu }_{0}}\]

    C)  \[6{{\mu }_{0}}\]                            

    D)         \[2{{\mu }_{0}}\]

    E)  zero

    Correct Answer: A

    Solution :

    Amperes law states that the line integral of\[\overrightarrow{B}\] around any closed path or circuit is equal to\[{{\mu }_{0}}\]times the total current crossing the area bounded by the closed path provided the electric field inside the loop remain constant. Thus,       \[\int{\overrightarrow{B}}.\overrightarrow{dl}={{\mu }_{0}}{{i}_{net}}\]                 \[={{\mu }_{0}}(3-2)={{\mu }_{0}}\]


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