CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    The first\[({{\Delta }_{i}}{{H}_{1}})\]and second\[({{\Delta }_{i}}{{H}_{2}})\]ionisation enthalpies (in\[kJ\text{ }mo{{l}^{-1}}\]) and the\[({{\Delta }_{eg}}H)\]electron gain enthalpy (in\[kJ\text{ }mo{{l}^{-1}}\]) of the elements I, II, III, IV and V are given below
    Element \[{{\Delta }_{i}}{{H}_{1}}\] \[{{\Delta }_{i}}{{H}_{2}}\] \[{{\Delta }_{eg}}H\]
    I 520 7300 \[-\,60\]
    II 419 3051 \[-\,48\]
    III 1681 3374 \[-\,328\]
    IV 1008 1846 \[-\,295\]
    V 2372 5251 \[+\,48\]
    The most reactive metal and the least reactive non-metal of these are respectively

    A)  l and V                                

    B)  V and II

    C)  II and V               

    D)         IV and V

    E)  V and III

    Correct Answer: C

    Solution :

    The element II has least ionization enthalpy and element V shows highest ionization enthalpy. So, amongst these, II represents most reactive metal and V represents least reactive non-metal.


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