A) \[M{{n}^{2+}}\]
B) \[HOCl\]
C) \[PbS\]
D) \[F{{e}^{2+}}\]
E) \[{{I}_{2}}\]
Correct Answer: E
Solution :
It reduces iodine to iodide ion in alkaline medium. \[{{I}_{2}}(s)+{{H}_{2}}{{O}_{2}}(aq)+2O{{H}^{-}}(aq)\xrightarrow{{}}\] \[2{{I}^{-}}(aq)+2{{H}_{2}}O(l)+{{O}_{2}}(g)\]
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