A) 3-methyl-2-butanol
B) 3-methyl-l-butanol
C) 1-butanol
D) 2-methyl-2-butanol
E) 2, 3-dimethyl-l-butanol
Correct Answer: D
Solution :
An equimolar mixture of cone.\[HCl\]and anhydrous\[ZnC{{l}_{2}}\]is called Lucas reagent. On treatement with Lucas reagent, tertiary alcohols gives precipitate immediately. This test is known as Lucas test. \[\underset{\begin{smallmatrix} 2-methyl-2-butanol \\ \,\,\,\,\,\,\,\,(3{}^\circ alcohol) \end{smallmatrix}}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{2}}-C{{H}_{3}}}}\,\xrightarrow[+anhy.\,ZnC{{l}_{2}}]{HCl}\] \[\underset{\begin{smallmatrix} \,\,\,\,\,\,\,\,\,2-chloro-2-methylbutane \\ (Turbidity\text{ }appears\text{ }immediately) \end{smallmatrix}}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} Cl \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{2}}-C{{H}_{3}}}}\,\]
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