CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    If the standard deviation of 3, 8, 6, 10, 12, 9, 11, 10, 12, 7 is 2.71, then the standard deviation of 30, 80, 60, 100, 120, 90, 110, 100, 120, 70 is

    A)  2.71                                      

    B)  \[27.1\]

    C)  \[(2.71)\sqrt{10}\]       

    D)         \[(27.1)\sqrt{2}\]

    E)  0.271

    Correct Answer: B

    Solution :

    We know that, the standard deviation is dependent on scale. If the values in the sample are multiplied by k, then the standard deviation will be multiplied by k. So, in given series/sample, multiplied by 10, then the resulting standard deviation is \[=10\times 2.71=27.1\]


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