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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    If\[(n+2)!=2550\times n!,\] then the value of n is equal to

    A)  8                            

    B)         49   

    C)  50                         

    D)         51

    E)  52

    Correct Answer: B

    Solution :

    \[(n+2)!=2550\times n!\] \[\Rightarrow \]               \[(n+2)(n+1).n!=2550.n!\] \[\Rightarrow \]               \[(n+2)(n+1)=2550\] \[\Rightarrow \]               \[{{n}^{2}}+3n-2548=0\] \[\Rightarrow \]               \[{{n}^{2}}+52n-49n-2548=0\] \[\Rightarrow \]               \[n(n+52)-49(n+52)=0\] \[\Rightarrow \]               \[(n+52)(n-49)=0\] \[\Rightarrow \]               \[n=-52,49\] \[\Rightarrow \]               \[n=49\]                               \[(here\,\,n\ne -52)\]


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