CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    A ball of mass m is dropped from a height h on a platform fixed at the top of a vertical spring, as shown in figure. The platform is depressed by a distance x. Then the spring constant is

    A) \[\frac{mg}{(h+x)}\]      

    B)        \[\frac{mg}{(h+2x)}\]    

    C)        \[\frac{2mg(h+x)}{{{x}^{2}}}\]  

    D)        \[\frac{mg}{(2h+x)}\]

    E) \[\frac{2mg}{(h+x)}\]

    Correct Answer: C

    Solution :

    Hence\[mg(h+x)=\frac{1}{2}k{{x}^{2}}\] \[k=\frac{2mg(h+x)}{{{x}^{2}}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner