2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force\[F=\frac{k}{{{r}^{2}}},\] where k is a constant.

    A)  The potential energy of the particle is zero

    B)  The potential energy of the particle is \[\frac{k}{r}\]

    C)  The total energy of the particle is \[-\frac{k}{2r}\]

    D)  The kinetic energy of the particle is \[-\frac{k}{r}\]

    E)  The potential energy of the particle is \[-\frac{k}{2r}\]

    Correct Answer: A

    Solution :

    For horizontal planes potential energy remains constant equal to zero, if we assume surface to be the zero level.


You need to login to perform this action.
You will be redirected in 3 sec spinner