A) 4L
B) \[\frac{L}{4}\]
C) \[\frac{L}{2}\]
D) 2L
E) \[\frac{L}{8}\]
Correct Answer: B
Solution :
We knows \[L=I\omega \] ... (i) \[{{L}^{2}}=2KI\] From Eq. (i) \[{{L}^{2}}=2K\frac{L}{\omega }\] \[L=\frac{2K}{\omega }\] \[L=\frac{2\left( \frac{K}{2} \right)}{2\omega }=\frac{L}{4}\]
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