CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    If the binding energy per nucleon of deuteron is 1.115 MeV, its mass defect in atomic mass unit is

    A)  0.0048                 

    B)         0.0024 

    C)         0.0012                 

    D)         0.0006

    E)  2.230

    Correct Answer: B

    Solution :

    Mass defect\[=\frac{2\times 1.115}{931}=0.0024\]unit


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