A) \[0{}^\circ \]
B) \[60{}^\circ \]
C) \[30{}^\circ \]
D) \[45{}^\circ \]
E) \[15{}^\circ \]
Correct Answer: C
Solution :
Given condition \[{{h}_{1}}={{h}_{2}}\] \[u_{1}^{2}{{\sin }^{2}}{{45}^{o}}=u_{2}^{2}{{\sin }^{2}}\theta \] \[{{\sin }^{2}}\theta =\frac{u_{1}^{2}}{u_{2}^{2}}{{\sin }^{2}}{{45}^{o}}\] \[=\frac{1}{2}.\frac{1}{2}=\frac{1}{4}\] \[\sin \theta =\frac{1}{2}\] \[\Rightarrow \] \[\theta ={{30}^{o}}\]You need to login to perform this action.
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