CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    The amplitude of a damped oscillator becomes \[\left( \frac{1}{3} \right)\]rd in 2s. If its amplitude after 6 s is\[\frac{1}{n}\]times the original amplitude, the value of n is

    A)  \[{{3}^{2}}\]                     

    B)         \[\sqrt[3]{2}\]                 

    C)  \[\sqrt[3]{3}\]                 

    D)         \[{{2}^{3}}\]

    E)  \[{{3}^{3}}\]

    Correct Answer: E

    Solution :

    We have \[A={{A}_{0}}{{e}^{-bt/2m}}\] In this case after 6s amplitudes becomes \[\frac{1}{27}\]times.


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