CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    Tube A has both ends open while tube B has one end closed. Otherwise they are identical. Their fundamental frequencies are in the ratio

    A)  4 : 1             

    B)                         2 : 1                      

    C)  1 : 4                      

    D)         1 : 2

    E)  2 : 3

    Correct Answer: B

    Solution :

    \[\frac{{{v}_{o}}}{{{v}_{c}}}=\frac{V/2\lambda }{V/4\lambda }=\frac{2}{1}\]


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