CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    Electric charge is uniformly distributed along a long straight wire of radius 1 mm. The charge per cm length of the wire is Q coulomb. Another cylindrical surface of radius 50 cm and length 1 m symmetrically encloses the wire. The total electric flux passing through the cylindrical surface is

    A)  \[\frac{Q}{{{\varepsilon }_{0}}}\]                            

    B)         \[\frac{100Q}{{{\varepsilon }_{0}}}\]                     

    C)  \[\frac{10Q}{\pi {{\varepsilon }_{0}}}\]                 

    D)         \[\frac{100Q}{\pi {{\varepsilon }_{0}}}\]

    E)  \[\frac{Q}{100{{\varepsilon }_{0}}}\]

    Correct Answer: B

    Solution :

    \[\phi =\frac{1}{60}q=\frac{100Q}{{{\varepsilon }_{0}}}\]


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