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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    A proton, a deuteron and an a-particle having the same kinetic energy are moving in circular trajectories in a constant magnetic field. If\[{{r}_{p}},{{r}_{d}}\]and\[{{r}_{\alpha }}\]denote respectively the radii of the trajectories of these particles, then

    A)  \[{{r}_{\alpha }}={{r}_{d}}>{{r}_{p}}\]                   

    B)  \[{{r}_{\alpha }}={{r}_{d}}={{r}_{p}}\]   

    C)         \[{{r}_{\alpha }}<{{r}_{d}}<{{r}_{p}}\]   

    D)         \[{{r}_{\alpha }}={{r}_{p}}>{{r}_{d}}\]

    E)  \[{{r}_{\alpha }}>{{r}_{d}}>{{r}_{p}}\]

    Correct Answer: A

    Solution :

    In this case \[R=\frac{mv}{qB}=\frac{\sqrt{2KE.m}}{qB}\] Here      \[R\propto \frac{\sqrt{m}}{q}=1:\sqrt{2}:1\] So,          \[{{r}_{\alpha }}={{r}_{d}}>{{r}_{p}}\]


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