CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    If\[{{E}_{0}}\]is the peak emf,\[{{I}_{0}}\]is the peak current and\[\phi \]is the phase difference between them, then the average power dissipation in the circuit is

    A)  \[\frac{1}{2}{{E}_{0}}{{I}_{0}}\]

    B)         \[\frac{{{E}_{0}}{{I}_{0}}}{\sqrt{2}}\]                     

    C)  \[\frac{1}{2}{{E}_{0}}{{I}_{0}}\sin \phi \]              

    D)         \[\frac{1}{2}{{E}_{0}}{{I}_{0}}\cos \phi \]

    E)  \[\frac{1}{2}{{E}_{0}}{{I}_{0}}\tan \phi \]

    Correct Answer: D

    Solution :

    By the definition we having standard result for this case average power dissipation in the circuit is\[\frac{1}{2}{{E}_{0}}{{I}_{0}}\cos \phi \].


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