A) \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\]
B) \[{{C}_{3}}{{H}_{6}}{{O}_{3}}\]
C) \[{{C}_{4}}{{H}_{8}}{{O}_{4}}\]
D) \[{{C}_{5}}{{H}_{10}}{{O}_{5}}\]
E) \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\]
Correct Answer: E
Solution :
\[\Delta {{T}_{f}}={{K}_{f}}\times m\] \[\because \] \[\Delta {{T}_{f}}=T_{f}^{o}-{{T}_{f}}\] \[=0{}^\circ -(-0.465{}^\circ )=0.465{}^\circ C\] \[\therefore \] \[0.465=1.86\times \frac{1.8}{M}\times \frac{1000}{40}\] or \[M=180\] empirical formula weight\[=12+1\times 2+16\] \[=30\] \[\because \] \[n=\frac{molecular\text{ }weight}{empirical\text{ }formula\text{ }weight}=\frac{180}{30}=6\] \[\therefore \]Molecular formula\[={{(C{{H}_{2}}O)}_{6}}\] \[={{C}_{2}}{{H}_{12}}{{O}_{6}}\] Thus, molecular formula of compound \[={{C}_{6}}{{H}_{12}}{{O}_{6}}\]
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