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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2000

  • question_answer
    If R is the radius of circum circle of the\[\Delta ABC\] and \[\Delta \]is its area, then:

    A) \[R=\frac{a+b+c}{\Delta }\]        

    B) \[R=\frac{a+b+c}{4\Delta }\]

    C)  \[R=\frac{abc}{4\Delta }\]                          

    D)  \[R=\frac{abc}{\Delta }\]

    Correct Answer: C

    Solution :

    Radius of circumcircle of\[\Delta ABC=R\]And its area \[=\Delta .\]We know that area of the triangle \[ABC(\Delta )=\frac{bc}{2}\sin A,\] \[a=2R\sin A\]or \[\sin =\frac{a}{2R}\] \[\Delta =\frac{1}{2}bc\frac{a}{2R}=\frac{abc}{4R}\]or \[R=\frac{abc}{4\Delta }\]


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