CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2000

  • question_answer
    A sound source is moving towards a stationary listener with 1/10th of the speed of the sound. The ratio of apparent to real speed will be:

    A)  \[{{\left( \frac{11}{10} \right)}^{2}}\]                    

    B) \[{{\left( \frac{9}{10} \right)}^{2}}\]

    C)  \[\frac{10}{9}\]                               

    D)  \[\frac{11}{10}\]

    Correct Answer: C

    Solution :

     Given: Velocity of listener =0 Velocity of source, \[a=\frac{1}{10}\times \upsilon =0.1\,\upsilon \](where \[\upsilon \] is the velocity of sound) From the Doppler's effect the apparent frequency is given by \[n'=\left( \frac{\upsilon }{\upsilon -a} \right)n=\left( \frac{\upsilon }{\upsilon -0.1\,\upsilon } \right)n\] \[\frac{n'}{n}=\frac{10}{9}\]


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