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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2000

  • question_answer
    The magnetic flux linked with a coil, in we bers, is given by the equations \[\text{o }\!\!|\!\!\text{ = 3}{{\text{t}}^{2}}+4t+9.\] Then the magnitude of induced emf at \[t=2\]second will be

    A)  2 volt                                   

    B)  4 volt

    C)  8 volt                                   

    D)  16 volt

    Correct Answer: D

    Solution :

     The magnetic flux linked with a coil is  given by \[\text{o }\!\!|\!\!\text{ =3}{{\text{t}}^{2}}+4t+9\] The relation for induced emf is                                 \[E=\frac{d\text{o }\!\!|\!\!\text{ }}{dt}\]                                 \[=\frac{d}{dt}(3{{t}^{2}}+4t+9)\]                                 \[=6t+4\] Hence, the induced emf at \[t=2\]second is                 \[{{E}_{2}}=6\times 2+4=12+4=16\,\text{volt}\]


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