CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    The   angle   between   the   lines\[{{x}^{2}}+4xy+{{y}^{2}}=0\]

    A) \[~{{60}^{o}}\]                                 

    B)  \[{{15}^{o}}\]

    C) \[~{{30}^{o}}\]                                 

    D) \[~{{45}^{o}}\]

    Correct Answer: A

    Solution :

    Equation of lines \[{{x}^{2}}+4xy+{{y}^{2}}=0,\]the standard equation for the pair of is \[a{{x}^{2}}+2hxy+by=0,\]comparing   the equation, \[a=1,h=2,b=1\] \[\Rightarrow \]               \[\tan \theta =\frac{2\sqrt{{{h}^{2}}-ab}}{a+b}\] \[\tan \theta =\frac{2\sqrt{4-1}}{2}\]\[\Rightarrow \]\[\tan \theta =\sqrt{3}\Rightarrow \theta ={{60}^{o}}\]


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