CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    In an experiment with Kund's tube, the distance between consecutive nodes is 5 cm, when air is inside and it is 13-4 cm, when hydrogen is inside then the velocity of sound in hydrogen will be   (velocity  of  sound  in  air =330 m/s):

    A) \[~884.4\text{ }m/s\]                    

    B)  \[984.4\text{ }m/s\]

    C) \[1084.4\text{ }m/s\]    

    D)  none of these

    Correct Answer: A

    Solution :

    Distance between two consecutive nodes with air\[{{l}_{A}}=5\,cm.\] Distance between two consecutive nodes with hydrogen? \[{{l}_{H}}=13.4\,cm.\] Velocity of sound in air\[~=330\,m/s\] The velocity of sound is given by \[\upsilon H=\upsilon A\frac{{{l}_{H}}}{{{l}_{A}}}=330\times \frac{13.4}{5}\]        \[=884.5\,m/s\]


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