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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    The general solution of the differential equation \[\frac{dy}{dx}=\frac{{{x}^{2}}}{{{y}^{2}}}\] is:

    A)  \[{{x}^{3}}-{{y}^{3}}=c\]                              

    B) \[{{x}^{3}}+{{y}^{3}}=c\]

    C)  \[{{x}^{2}}+{{y}^{2}}=c\]                             

    D)  \[{{x}^{2}}-{{y}^{2}}=c\]

    Correct Answer: A

    Solution :

    \[{{y}^{2}}dy={{x}^{2}}dx\] Integrating we get                 \[\frac{{{y}^{3}}}{3}=\frac{{{x}^{3}}}{3}+c\Rightarrow {{y}^{3}}-{{x}^{3}}=c\]


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