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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    Let \[f:R\to R\]  be   defined   by \[f(x)=3x+4.\]Then \[{{f}^{-1}}(x)\]is:

    A)  \[\frac{x+4}{3}\]                             

    B) \[\frac{x}{3}-4\]

    C) \[3x+4\]                              

    D)  none of these

    Correct Answer: A

    Solution :

    Let \[{{f}^{-1}}(x)=y\]then \[x=f(y)=3y-4\Rightarrow \]\[y=\frac{x+4}{3}\] \[{{f}^{-1}}(x)=y\Rightarrow {{f}^{-1}}(x)=\frac{x+4}{3}\]


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