A) \[\frac{{{\mu }_{0}}ne}{2r}\]
B) \[\frac{{{\mu }_{0}}{{n}^{2}}e}{2r}\]
C) \[\frac{{{\mu }_{0}}ne}{2\pi r}\]
D) zero
Correct Answer: C
Solution :
Radius of circular path \[=r\] (given)rotation of the electron per second\[~=n\] From the formula the magnetic field produced by the electron at the centre is given by \[=\frac{{{\mu }_{0}}ne}{r}\]
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