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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    A train is moving towards north with a speed of 180 km/hr. If the vertical component of the earth's magnetic field is \[0.2\times {{10}^{-4}}T,\]the e .m. f. induced, in the axle 1-5m long, is:

    A)  1.5 mV                                

    B)  15 mV

    C)  5.4 mV                                

    D)  54 mV

    Correct Answer: A

    Solution :

    Given: Length of the axle \[l=1.5\,m\] The magnetic field \[B=0.2\times {{10}^{-4}}\]tesla The speed of the train\[~=\text{ }180\text{ km/hour}\] \[=180\times \frac{5}{18}=50\,m/s\] From the formula e. m. f. is given by \[E=B\upsilon l\] \[=0.2\times {{10}^{-4}}\times 50\times 1.5\] \[=1.5\times {{10}^{-3}}=1.5\,mV\]


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