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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    A block of mass 1kg slide down a rough inclined plane of inclination \[{{60}^{o}}\]starting from its top. If coefficient of kinetic friction is 0.5 and length of the plane\[d=1\text{ }m\]then work done against friction is:

    A)  2.45 J                                   

    B)  4.9J

    C)  9.8 J                                     

    D)  19.6J

    Correct Answer: A

    Solution :

    Mass of the block\[~m=1\text{ }kg\] Inclination \[\theta ={{60}^{o}}\] Coefficient of friction \[\mu =0.5\] Length of the plane\[d=1\,m\]   (given) The force experienced by the body \[F=\mu \,mg\,\cos \theta \] \[=0.5\times 1\times 9.8\times \cos {{60}^{o}}\] \[=4.9\times 0.5=2.45\,N\] Therefore work done \[=F.d=2.45\times 1=2.45\,J\]


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